CUET · PHYSICS · PYQ PAPER 2023
To increase the current sensitivity of a moving coil galvanometer by 75%, its resistance is increased so that the new resistance becomes twice its initial resistance. By what factor does its voltage sensitivity change ?
- A decreases by 12.5%
- B increases by 25%
- C decreases by 25%
- D increases by 12.5%
Answer & Solution
Correct Answer
(A) decreases by 12.5%
Step-by-step Solution
Detailed explanation
\(V_s = \frac{I_s}{R}\) \(V_s' = \frac{I_s'}{R'} = \frac{1.75 I_s}{2R}\) \(\frac{V_s'}{V_s} = \frac{1.75 I_s / (2R)}{I_s / R} = \frac{1.75}{2} = 0.875\) Change \( = (0.875 - 1) \times 100\% = -12.5\%\) Voltage sensitivity decreases by 12.5%.
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