CUET · PHYSICS · PYQ PAPER 2025
To increase the current sensitivity of a moving coil galvanometer by 50%, its resistance is increased so that the new resistance becomes twice its initial resistance. By what percentage does its voltage sensitivity change?
- A It increases by 75%.
- B It decreases by 75%.
- C It increases by 25%.
- D It decreases by 25%.
Answer & Solution
Correct Answer
(D) It decreases by 25%.
Step-by-step Solution
Detailed explanation
\(V_s = I_s/R\) \(V_s' = I_s'/R' = (1.5 I_s) / (2R) = 0.75 (I_s/R) = 0.75 V_s\) \(\% \Delta V_s = ((V_s' - V_s) / V_s) \times 100\%\) \(\% \Delta V_s = ((0.75 V_s - V_s) / V_s) \times 100\%\) \(\% \Delta V_s = -0.25 \times 100\%\) \(\% \Delta V_s = -25\%\) Decreases by 25%.
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