CUET · PHYSICS · PYQ PAPER 2023
Time period of oscillation of a bar magnet in a uniform magnetic field is \( T_o \). The magnet is cut into 3 equal parts transverse to its length. The new time period of oscillation of one part will be :
- A \( T_o \)
- B \( \frac{T_o}{2} \)
- C \( \frac{T_o}{3} \)
- D \( \frac{T_o}{4} \)
Answer & Solution
Correct Answer
(C) \( \frac{T_o}{3} \)
Step-by-step Solution
Detailed explanation
\( T_o = 2\pi \sqrt{\frac{I}{MB}} \) \( M' = \frac{M}{3} \), \( I' = \frac{I}{27} \) \( T' = 2\pi \sqrt{\frac{I'}{M'B}} = 2\pi \sqrt{\frac{I/27}{(M/3)B}} = 2\pi \sqrt{\frac{I}{9MB}} = \frac{1}{3} \left( 2\pi \sqrt{\frac{I}{MB}} \right) = \frac{T_o}{3} \)
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