CUET · PHYSICS · PYQ PAPER 2025
Three resistances of 1 \(\Omega\), 2 \(\Omega\) and 3 \(\Omega\) are given. In order to obtain an equivalent resistance of 11/3 \(\Omega\) they are to be connected as
- A 3 \(\Omega\) in series with parallel combination of 1 \(\Omega\) and 2 \(\Omega\)
- B 3 \(\Omega\) in parallel with series combination of 1 \(\Omega\) and 2 \(\Omega\)
- C all in parallel
- D 1\(\Omega\) in series with parallel combination of 2 \(\Omega\) and 3 \(\Omega\)
Answer & Solution
Correct Answer
(A) 3 \(\Omega\) in series with parallel combination of 1 \(\Omega\) and 2 \(\Omega\)
Step-by-step Solution
Detailed explanation
\(R_{p} = \frac{1 \times 2}{1 + 2} = \frac{2}{3} \, \Omega\) \(R_{eq} = 3 + \frac{2}{3} = \frac{9+2}{3} = \frac{11}{3} \, \Omega\)
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