CUET · PHYSICS · PYQ PAPER 2025
Three capacitors of capacitances 2 \(\mu F\), 3 \(\mu F\) and 6 \(\mu F\) are connected in series. The combination is connected to a 12 V supply. The respective potential differences across them will be
- A 3 V, 4 V and 5 V
- B 2 V, 4 V and 6 V
- C 6 V, 4 V and 2 V
- D 4 V across each capacitor
Answer & Solution
Correct Answer
(C) 6 V, 4 V and 2 V
Step-by-step Solution
Detailed explanation
\( \frac{1}{C_{eq}} = \frac{1}{2 \mu F} + \frac{1}{3 \mu F} + \frac{1}{6 \mu F} = \frac{3+2+1}{6 \mu F} = 1 \mu F \) \( C_{eq} = 1 \mu F \) \( Q = C_{eq} V = (1 \mu F)(12 V) = 12 \mu C \) \( V_1 = \frac{Q}{C_1} = \frac{12 \mu C}{2 \mu F} = 6 V \)…
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