CUET · PHYSICS · PYQ PAPER 2025
Three capacitors, C1, C2, C3 are connected in series. This combination is connected in parallel with capacitor C4. C1 = C2 = C3 = 30 \( \mu F \) and C4 = 10 \( \mu F \). Now a potential 400 V is applied across the combination. The total charge across the combination of capacitors is
- A \( 8 \times 10^{-3} \, C \)
- B \( 4 \times 10^{-3} \, C \)
- C \( 3.6 \times 10^{-3} \, C \)
- D \( 4 \times 10^{-3} \, C \)
Answer & Solution
Correct Answer
(A) \( 8 \times 10^{-3} \, C \)
Step-by-step Solution
Detailed explanation
\( C_{series} = \left(\frac{1}{C_1} + \frac{1}{C_2} + \frac{1}{C_3}\right)^{-1} = \left(\frac{1}{30 \mu F} + \frac{1}{30 \mu F} + \frac{1}{30 \mu F}\right)^{-1} = 10 \mu F \) \( C_{total} = C_{series} + C_4 = 10 \mu F + 10 \mu F = 20 \mu F \)…
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