CUET · PHYSICS · PYQ PAPER 2025
There exists a horizontal magnetic field in space of value \( B = 9 \times 10^{-4} \text{ T} \). A magnetic bar of magnetic moment \( M = 9 \times 10^3 \text{ J/T} \) is placed at an angle \( \theta_i = 60^\circ \) to the field and is free to rotate. Finally, it comes to a position parallel to the field. Work done by magnetic field on the magnetic bar will be
- A \( 1.4 \times 10^{-2} \text{ J} \)
- B \(-40.5 J \)
- C \(-4.05 J \)
- D \(4.05 J \)
Answer & Solution
Correct Answer
(D) \(4.05 J \)
Step-by-step Solution
Detailed explanation
\( W = M B (\cos \theta_f - \cos \theta_i) \) \( W = (9 \times 10^3 \text{ J/T}) (9 \times 10^{-4} \text{ T}) (\cos 0^\circ - \cos 60^\circ) \) \( W = 8.1 \text{ J} (1 - 0.5) \) \( W = 4.05 \text{ J} \)
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