CUET · PHYSICS · PYQ PAPER 2025
There are two electric charges, \( Q_1 \) and \( Q_2 \), placed in vacuum. Identify the correct statements from the following
1. There will be an electrostatic force between them.
2. If these charges are placed in water, the force between them will increase.
3. The electrostatic force between them is a conservative force.
4. If both of the charges are doubled as \( 2Q_1 \) and \( 2Q_2 \), then the force between them will become 4 times.
Choose the correct answer from the options given below:
- A (A) and (D) only
- B (A), (C) and (D) only
- C (A) and (C) only
- D (A), (B) and (C) only
Answer & Solution
Correct Answer
(B) (A), (C) and (D) only
Step-by-step Solution
Detailed explanation
1. Correct. 2. \( F_{medium} = \frac{F_{vacuum}}{\epsilon_r} \). For water, \( \epsilon_r > 1 \), so force decreases. Incorrect. 3. Correct. 4. \( F' = k \frac{(2Q_1)(2Q_2)}{r^2} = 4 k \frac{Q_1 Q_2}{r^2} = 4F \). Correct. Correct statements are 1, 3, and 4 (A, C, and D). (A),…
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