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CUET · PHYSICS · PYQ PAPER 2023

The wavelength of radiation emitted, when \( \text{He}^{+} \) makes a transition from the state n = 3 to the state n = 2 will be :
(Take Rydberg constant \( R = 1.097 \times 10^{7} \text{ m}^{-1} \))

  1. A 1.641 nm
  2. B 164.1 nm
  3. C 16.41 nm
  4. D 1641 nm
Verified Solution

Answer & Solution

Correct Answer

(B) 164.1 nm

Step-by-step Solution

Detailed explanation

\( \frac{1}{\lambda} = R Z^2 \left( \frac{1}{n_1^2} - \frac{1}{n_2^2} \right) \) \( \frac{1}{\lambda} = (1.097 \times 10^7 \text{ m}^{-1}) (2^2) \left( \frac{1}{2^2} - \frac{1}{3^2} \right) \)…