CUET · PHYSICS · PYQ PAPER 2023
The wavelength of radiation emitted, when \( \text{He}^{+} \) makes a transition from the state n = 3 to the state n = 2 will be :
(Take Rydberg constant \( R = 1.097 \times 10^{7} \text{ m}^{-1} \))
- A 1.641 nm
- B 164.1 nm
- C 16.41 nm
- D 1641 nm
Answer & Solution
Correct Answer
(B) 164.1 nm
Step-by-step Solution
Detailed explanation
\( \frac{1}{\lambda} = R Z^2 \left( \frac{1}{n_1^2} - \frac{1}{n_2^2} \right) \) \( \frac{1}{\lambda} = (1.097 \times 10^7 \text{ m}^{-1}) (2^2) \left( \frac{1}{2^2} - \frac{1}{3^2} \right) \)…
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