CUET · PHYSICS · PYQ PAPER 2023
The wavelength of light from the spectral emission line of sodium is 662 nm.
The kinetic energy at which an electron would have the same de-Broglie wavelength would be:
(Given: \( h = 6.62 \times 10^{-34} \text{ J s}, m_e = 9 \times 10^{-31} \text{ kg} \))
- A \( 5.5 \times 10^{-25} \text{ J} \)
- B \( 5.5 \times 10^{-24} \text{ J} \)
- C \( 18 \times 10^{-23} \text{ J} \)
- D \( 4.5 \times 10^{-22} \text{ J} \)
Answer & Solution
Correct Answer
(A) \( 5.5 \times 10^{-25} \text{ J} \)
Step-by-step Solution
Detailed explanation
\( KE = \frac{h^2}{2m_e\lambda^2} \) \( KE = \frac{(6.62 \times 10^{-34})^2}{2 \times 9 \times 10^{-31} \times (662 \times 10^{-9})^2} \) \( KE = \frac{(6.62)^2 \times 10^{-68}}{18 \times 10^{-31} \times (100 \times 6.62)^2 \times 10^{-18}} \)…
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