CUET · PHYSICS · PYQ PAPER 2023
The velocity and acceleration vectors of a particle moving in a magnetic field are given by : \(\vec{v}=3 \hat{i}+4 \hat{j}\) and \(\vec{a}=2 \hat{i}+\hat{j}\) respectively, Then :
(A) the magnetic field is along \(z\)-direction
(B) \(v=3\)
(C) the kinetic energy of the particle is constant
(D) the acceleration is in x-z plane
(E) the particle is moving in \(x-y\) plane
- A The kinetic energy of the particle remains constant.
- B The particle is moving in the x-y plane.
- C The magnitude of the velocity is 3 units.
- D The acceleration vector lies in the x-z plane.
Answer & Solution
Correct Answer
(B) The particle is moving in the x-y plane.
Step-by-step Solution
Detailed explanation
\(\vec{v} = 3 \hat{i} + 4 \hat{j}\) has no z-component. \(\vec{a} = 2 \hat{i} + \hat{j}\) has no z-component. Therefore, the particle is moving in the x-y plane.
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