CUET · PHYSICS · PYQ PAPER 2025
The torque acting on a magnet of magnetic length 8 cm and pole strength 20 A m placed in a magnetic field of \( 3 \times 10^{-5} \, T \) at an angle of \( \pi/6 \) rad will be
- A \( 2.4 \times 10^{-4} \, Nm \)
- B \( 2.4 \times 10^{-5} \, Nm \)
- C \( 4.2 \times 10^{-3} \, Nm \)
- D \( 4.2 \times 10^{-5} \, Nm \)
Answer & Solution
Correct Answer
(B) \( 2.4 \times 10^{-5} \, Nm \)
Step-by-step Solution
Detailed explanation
\(M = q_m \times 2l = 20 \times 0.08 = 1.6 \text{ A m}^2\) \( \tau = MB \sin\theta = 1.6 \times 3 \times 10^{-5} \times \sin(\pi/6) = 1.6 \times 3 \times 10^{-5} \times 0.5 = 2.4 \times 10^{-5} \text{ Nm} \)
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