CUET · PHYSICS · PYQ PAPER 2023
The threshold wavelength of silver is \( 3250 \times 10^{-10} \text{ m} \). The velocity of the electron ejected from the silver surface by ultra violet light of wavelength \( 2536 \times 10^{-10} \text{ m} \) is approximately : (Given \( h = 4.14 \times 10^{-15} \text{ eVs} \))
- A \( 6 \times 10^5 \text{ ms}^{-1} \)
- B \( 0.6 \times 10^6 \text{ ms}^{-1} \)
- C \( 61 \times 10^3 \text{ ms}^{-1} \)
- D \( 0.3 \times 10^6 \text{ ms}^{-1} \)
Answer & Solution
Correct Answer
(A) \( 6 \times 10^5 \text{ ms}^{-1} \)
Step-by-step Solution
Detailed explanation
\( K_{max} = hc \left( \frac{1}{\lambda} - \frac{1}{\lambda_0} \right) \) \( K_{max} = (4.14 \times 10^{-15} \text{ eVs})(3 \times 10^8 \text{ m/s}) \left( \frac{1}{2536 \times 10^{-10} \text{ m}} - \frac{1}{3250 \times 10^{-10} \text{ m}} \right) \)…
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