CUET · PHYSICS · PYQ PAPER 2023
The speed of light in a medium whose critical angle is \(60^{\circ}\) will be:
- A \(2.6 \times 10^8 m / s\)
- B \(1.5 \times 10^8 m / s\)
- C \(3 \times 10^8 m / s\)
- D \(2 \times 10^8 m / s\)
Answer & Solution
Correct Answer
(A) \(2.6 \times 10^8 m / s\)
Step-by-step Solution
Detailed explanation
\( n = \frac{1}{\sin\theta_c} = \frac{1}{\sin(60^\circ)} = \frac{1}{\sqrt{3}/2} = \frac{2}{\sqrt{3}} \) \( v = \frac{c}{n} = \frac{3 \times 10^8 \, \text{m/s}}{2/\sqrt{3}} = 3 \times 10^8 \times \frac{\sqrt{3}}{2} = 2.598 \times 10^8 \, \text{m/s} \)…
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