CUET · PHYSICS · PYQ PAPER 2025
The separation between the plates of a parallel plate capacitor of capacitance 2 pF is 0.5 mm . The area of the plates of the capacitor is (Given: \(\varepsilon_0=8.85 \times 10^{-12} C ^2 N^{-1} m^{-2}\) )
- A \(520 cm^2\)
- B \(71 cm^2\)
- C \(113 cm^2\)
- D \(1.13 cm^2\)
Answer & Solution
Correct Answer
(D) \(1.13 cm^2\)
Step-by-step Solution
Detailed explanation
\(A = \frac{C d}{\varepsilon_0}\) \(A = \frac{(2 \times 10^{-12} \text{ F}) (0.5 \times 10^{-3} \text{ m})}{8.85 \times 10^{-12} \text{ C}^2 \text{ N}^{-1} \text{ m}^{-2}}\) \(A \approx 1.13 \times 10^{-4} \text{ m}^2 = 1.13 \text{ cm}^2\)
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