CUET · PHYSICS · PYQ PAPER 2025
The self-inductance of an inductance coil having 100 turns is 20 mH. The total flux through the coil for a current of 40 mA is :
- A \( 8 \times 10^{-3} \text{ Wb} \)
- B \( 4 \times 10^{-3} \text{ Wb} \)
- C \( 8 \times 10^{-4} \text{ Wb} \)
- D \( 4 \times 10^{-4} \text{ Wb} \)
Answer & Solution
Correct Answer
(C) \( 8 \times 10^{-4} \text{ Wb} \)
Step-by-step Solution
Detailed explanation
\( \Phi = L I \) \( \Phi = (20 \times 10^{-3} \text{ H}) \times (40 \times 10^{-3} \text{ A}) \) \( \Phi = 8 \times 10^{-4} \text{ Wb} \)
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