CUET · PHYSICS · PYQ PAPER 2025
The resistance of a galvanometer is G = 30 \( \Omega \). It gives full scale deflection for \( I_g = 2 \text{ mA} \). It is to be converted into an ammeter to measure current I = 0.3 A. The value of the shunt required is approximately
- A 0.2 \( \Omega \)
- B 2.03 \( \Omega \)
- C 0.06 \( \Omega \)
- D 0.09 \( \Omega \)
Answer & Solution
Correct Answer
(A) 0.2 \( \Omega \)
Step-by-step Solution
Detailed explanation
\(S = \frac{I_g G}{I - I_g}\) \(S = \frac{(2 \times 10^{-3} \text{ A})(30 \, \Omega)}{0.3 \text{ A} - 2 \times 10^{-3} \text{ A}}\) \(S \approx 0.2 \, \Omega\)
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