CUET · PHYSICS · PYQ PAPER 2023
The ratio of nucleus density of nitrogen nucleus (\( {}^{14}_7\text{N} \)) to the nucleus density of oxygen nucleus (\( {}^{16}_8\text{O} \)) will be :
- A 1 : 4
- B 4 : 1
- C 1 : 1
- D 1 : 16
Answer & Solution
Correct Answer
(C) 1 : 1
Step-by-step Solution
Detailed explanation
\(\rho = \frac{\text{Mass}}{\text{Volume}} = \frac{A \cdot m_p}{\frac{4}{3} \pi R_0^3 A} = \frac{m_p}{\frac{4}{3} \pi R_0^3}\) \(\frac{\rho_{\text{Nitrogen}}}{\rho_{\text{Oxygen}}} = \frac{\frac{m_p}{\frac{4}{3} \pi R_0^3}}{\frac{m_p}{\frac{4}{3} \pi R_0^3}} = 1:1\)
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