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CUET · PHYSICS · PYQ PAPER 2023

The ratio of nucleus density of nitrogen nucleus (\( {}^{14}_7\text{N} \)) to the nucleus density of oxygen nucleus (\( {}^{16}_8\text{O} \)) will be :

  1. A 1 : 4
  2. B 4 : 1
  3. C 1 : 1
  4. D 1 : 16
Verified Solution

Answer & Solution

Correct Answer

(C) 1 : 1

Step-by-step Solution

Detailed explanation

\(\rho = \frac{\text{Mass}}{\text{Volume}} = \frac{A \cdot m_p}{\frac{4}{3} \pi R_0^3 A} = \frac{m_p}{\frac{4}{3} \pi R_0^3}\) \(\frac{\rho_{\text{Nitrogen}}}{\rho_{\text{Oxygen}}} = \frac{\frac{m_p}{\frac{4}{3} \pi R_0^3}}{\frac{m_p}{\frac{4}{3} \pi R_0^3}} = 1:1\)