CUET · PHYSICS · PYQ PAPER 2025
The radius of the arc BD representing a wire is 60 cm. The magnitude of the magnetic field produced at centre C, if a current of 3.0 A flows in the wire, will be:

- A \( \frac{5\pi}{6} \times 10^{-7} \, \text{T} \)
- B \( \frac{5\pi}{12} \times 10^{-7} \, \text{T} \)
- C \( \frac{5}{6} \times 10^{-7} \, \text{T} \)
- D \( \frac{\pi}{6} \times 10^{-7} \, \text{T} \)
Answer & Solution
Correct Answer
(A) \( \frac{5\pi}{6} \times 10^{-7} \, \text{T} \)
Step-by-step Solution
Detailed explanation
\( B = \frac{\mu_0 I}{4\pi r} \theta \) \( B = \frac{(4\pi \times 10^{-7} \, \text{T m/A}) \times 3.0 \, \text{A}}{4\pi \times 0.60 \, \text{m}} \times \frac{\pi}{6} \, \text{rad} \) \( B = \frac{3.0 \times 10^{-7}}{0.60} \times \frac{\pi}{6} \, \text{T} \)…
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