CUET · PHYSICS · PYQ PAPER 2025
The plates of a parallel plate capacitor are separated by a distance d with air as medium between the plates. In order to increase its capacitance by 60%, a slab of dielectric constant 5 having the same area as that of plates is introduced between the plates. The thickness of the dielectric slab is :
- A \( \frac{5}{8}d \)
- B \( \frac{8}{23}d \)
- C \( \frac{6}{19}d \)
- D \( \frac{15}{32}d \)
Answer & Solution
Correct Answer
(D) \( \frac{15}{32}d \)
Step-by-step Solution
Detailed explanation
\( \frac{\epsilon_0 A}{d - t + \frac{t}{\kappa}} = 1.6 \frac{\epsilon_0 A}{d} \) \( d = 1.6 \left( d - t + \frac{t}{5} \right) \) \( d = 1.6d - 1.6t + 0.32t \) \( -0.6d = -1.28t \) \( t = \frac{0.6d}{1.28} = \frac{60d}{128} \) \( t = \frac{15d}{32} \)
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