CUET · PHYSICS · PYQ PAPER 2025
The peak value of current in an ideal inductor of \((2/\pi) \text{ H}\) inductance connected to a 200 V, 50 Hz ac supply will be
- A \(1 A\)
- B \(1.414 A\)
- C \(1.5 A\)
- D \(2 A\)
Answer & Solution
Correct Answer
(B) \(1.414 A\)
Step-by-step Solution
Detailed explanation
\(X_L = 2\pi f L\) \(X_L = 2\pi (50 \text{ Hz}) \left(\frac{2}{\pi} \text{ H}\right) = 200 \Omega\) \(V_{peak} = V_{rms}\sqrt{2} = 200\sqrt{2} \text{ V}\) \(I_{peak} = \frac{V_{peak}}{X_L}\)…
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