CUET · PHYSICS · PYQ PAPER 2023
The number of free electrons per 100 mm of ordinary copper wire is 2 \(\times 10^{21}\). The average drift speed of electrons is 0.25 mm/s. The amount of current flowing would be : (e = 1.6 \(\times 10^{-19}\) C)
- A 0.2 A
- B 2.5 A
- C 5.0 A
- D 0.8 A
Answer & Solution
Correct Answer
(D) 0.8 A
Step-by-step Solution
Detailed explanation
\( I = \frac{N}{L} v_d e \) \( I = \frac{2 \times 10^{21}}{0.1 \text{ m}} (0.25 \times 10^{-3} \text{ m/s}) (1.6 \times 10^{-19} \text{ C}) \) \( I = 0.8 \text{ A} \)
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