CUET · PHYSICS · PYQ PAPER 2023
The number densities of electrons and holes in pure silicon at 273 K are equal and their values are \( 1.5 \times 10^{16} \text{ m}^{-3} \). On doping, the hole density increases to \( 4.5 \times 10^{27} \text{ m}^{-3} \). The electron density in the doped silicon will be :
- A \( 5 \times 10^4 \text{ m}^{-3} \)
- B \( 5 \times 10^8 \text{ m}^{-3} \)
- C \( 5 \times 10^9 \text{ m}^{-3} \)
- D \( 5 \times 10^7 \text{ m}^{-3} \)
Answer & Solution
Correct Answer
(A) \( 5 \times 10^4 \text{ m}^{-3} \)
Step-by-step Solution
Detailed explanation
\( n \cdot p = n_i^2 \) \( n = \frac{n_i^2}{p} = \frac{(1.5 \times 10^{16})^2}{4.5 \times 10^{27}} \) \( n = \frac{2.25 \times 10^{32}}{4.5 \times 10^{27}} = 0.5 \times 10^5 \text{ m}^{-3} \) \( n = 5 \times 10^4 \text{ m}^{-3} \)
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