CUET · PHYSICS · PYQ PAPER 2023
The maximum power drawn out of cell is given by : (E is emf, r is internal resistance)
- A \(\frac{E^2}{2 r}\)
- B \(\frac{E^2}{4 r}\)
- C \(\frac{E^2}{r}\)
- D \(\frac{E^2}{3 r}\)
Answer & Solution
Correct Answer
(B) \(\frac{E^2}{4 r}\)
Step-by-step Solution
Detailed explanation
\( P = \frac{E^2 R}{(R+r)^2} \) \( \text{For maximum power, } R=r \implies P_{max} = \frac{E^2 r}{(r+r)^2} = \frac{E^2}{4r} \)
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