CUET · PHYSICS · PYQ PAPER 2025
The magnifying power of a telescope is 6 in normal adjustment. The distance between its two lenses is 35 cm. The focal lengths of objective and eye-piece are, respectively:
- A 30 cm, 5 cm
- B 25 cm, 5 cm
- C 5 cm, 30 cm
- D 20 cm, 15 cm
Answer & Solution
Correct Answer
(A) 30 cm, 5 cm
Step-by-step Solution
Detailed explanation
\(M = f_o/f_e\) \(6 = f_o/f_e \Rightarrow f_o = 6f_e\) \(L = f_o + f_e\) \(35 \text{ cm} = 6f_e + f_e = 7f_e\) \(f_e = 35/7 = 5 \text{ cm}\) \(f_o = 6 \times 5 = 30 \text{ cm}\) \(30 \text{ cm}, 5 \text{ cm}\)
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