CUET · PHYSICS · PYQ PAPER 2025
The magnetisation at the centre of a bar magnet (magnetic length 10 cm), having pole strength 6.3 A m, and area of cross-section \(A = 0.70 \text{ cm}^2\) is
- A \(1.1 \times 10^5 \text{ A m}^{-1}\)
- B \(9.0 \times 10^4 \text{ A m}^{-1}\)
- C \(9.0 \times 10^3 \text{ A m}^{-1}\)
- D \(9.0 \times 10^{-4} \text{ A m}^{-1}\)
Answer & Solution
Correct Answer
(B) \(9.0 \times 10^4 \text{ A m}^{-1}\)
Step-by-step Solution
Detailed explanation
\(M = \frac{m}{A}\) \(M = \frac{6.3 \text{ A m}}{0.70 \times 10^{-4} \text{ m}^2}\) \(M = 9.0 \times 10^4 \text{ A m}^{-1}\)
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