CUET · PHYSICS · PYQ PAPER 2023
The magnetic moment of a current loop is \( 2.1 \times 10^{-25} \text{ A m}^{2} \). The magnetic field on the axis of the loop at a distance of 1.0 \( \text{\AA} \) from the loop would be : (Given radius of loop negligible)
- A \( 24 \times 10^{-2} \text{ T} \)
- B \( 2.4 \times 10^{2} \text{ T} \)
- C \( 4.2 \times 10^{-2} \text{ T} \)
- D \( 42 \times 10^{2} \text{ T} \)
Answer & Solution
Correct Answer
(C) \( 4.2 \times 10^{-2} \text{ T} \)
Step-by-step Solution
Detailed explanation
\( B = \frac{\mu_0}{4\pi} \frac{2M}{x^3} \) \( B = (10^{-7}) \frac{2 \times (2.1 \times 10^{-25})}{(1.0 \times 10^{-10})^3} \) \( B = 4.2 \times 10^{-2} \text{ T} \)
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