CUET · PHYSICS · PYQ PAPER 2023
The magnetic energy stored in a current carrying solenoid is (if \(B=\) magnetic field, \(1=\) length of solenoid, \(A=\) area of cross section of solenoid) :
- A \(\frac{ B ^2}{2 \mu_0}\)
- B \(\frac{\mu_0 B^2}{2}\)
- C \(\frac{\mu_0 B^2 Al }{2}\)
- D \(\frac{ B ^{ 2 } A l }{ 2 \mu_0}\)
Answer & Solution
Correct Answer
(D) \(\frac{ B ^{ 2 } A l }{ 2 \mu_0}\)
Step-by-step Solution
Detailed explanation
Total magnetic energy is calculated by multiplying the magnetic energy density \(\left(\frac{B^2}{2 \mu_0}\right)\) by the total volume of the solenoid \((A l)\). D) \(\frac{B^2 A I}{2 \mu_0}\)
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