CUET · PHYSICS · PYQ PAPER 2025
The kinetic energy of an electron in a given orbit in a hydrogen atom is : (symbols have their usual meaning)
- A \( \frac{e^2}{4\pi\epsilon_0 r} \)
- B \( \frac{e^3}{8\pi\epsilon_0 r} \)
- C \( \frac{e^2}{8\pi\epsilon_0 r} \)
- D \( \frac{e^2}{3\pi\epsilon_0 r} \)
Answer & Solution
Correct Answer
(C) \( \frac{e^2}{8\pi\epsilon_0 r} \)
Step-by-step Solution
Detailed explanation
\( PE = -\frac{e^2}{4\pi\epsilon_0 r} \) \( KE = -\frac{1}{2} PE \) \( KE = -\frac{1}{2} \left( -\frac{e^2}{4\pi\epsilon_0 r} \right) \) \( KE = \frac{e^2}{8\pi\epsilon_0 r} \)
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