CUET · PHYSICS · PYQ PAPER 2025
The internal resistance of a cell of emf 2 V is 0.1 \( \Omega \). It is connected to an external resistance of 3.9 \( \Omega \). The terminal potential difference across the cell will be
- A 0.5 V
- B 1.5 V
- C 1.95 V
- D 2 V
Answer & Solution
Correct Answer
(C) 1.95 V
Step-by-step Solution
Detailed explanation
\(I = \frac{E}{R+r} = \frac{2}{3.9 + 0.1} = 0.5 \text{ A}\) \(V = IR = 0.5 \times 3.9 = 1.95 \text{ V}\)
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