CUET · PHYSICS · PYQ PAPER 2025
The intensity of transmitted light is maximum when a Polaroid sheet (\( P_2 \)) is rotated between two crossed Polaroids, \( P_1 \) and \( P_3 \) when
- A The angle between \( P_1 \) and \( P_2 \) and \( P_2 \) and \( P_3 \) will be \(\frac{\pi}{4}\)
- B Polaroids \( P_1 \) and \( P_2 \) are crossed
- C angle between \( P_1 \) and \( P_2 \) is \(\frac{\pi}{3}\) and between \( P_2 \) and \( P_3 \) is \(\frac{\pi}{6}\)
- D the angle between \( P_2 \) and \( P_3 \) does not matter
Answer & Solution
Correct Answer
(A) The angle between \( P_1 \) and \( P_2 \) and \( P_2 \) and \( P_3 \) will be \(\frac{\pi}{4}\)
Step-by-step Solution
Detailed explanation
The angle between \(P_1\) and \(P_2\) and \(P_2\) and \(P_3\) will be \(\frac{\pi}{4}\) \(I_t = \frac{I_0}{8} \sin^2(2\theta)\) For maximum intensity, \(\sin^2(2\theta) = 1\) \(2\theta = \frac{\pi}{2}\) \(\theta = \frac{\pi}{4}\) Angle between \( P_1 \) and \( P_2 \) is…
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