CUET · PHYSICS · PYQ PAPER 2023
The instantaneous power supplied to a capacitor is given by\(P_c=i_m \cos (\omega t) v_m \sin (\omega t)\).
The average power over a complete cycle would be:
- A \(\frac{\cos^2 \omega t}{2}\)
- B \(\frac{\sin^2 \omega t}{2}\)
- C Zero
- D -1
Answer & Solution
Correct Answer
(C) Zero
Step-by-step Solution
Detailed explanation
\(P_c = i_m v_m \sin (\omega t) \cos (\omega t) = \frac{1}{2} i_m v_m \sin (2\omega t)\) The average value of a sinusoidal function over a complete cycle is zero. Average power \(= 0\)
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