CUET · PHYSICS · PYQ PAPER 2023
The frequency of a photon whose energy is 66.3 eV would be
(Given \( h = 6.63 \times 10^{-34} \text{ Js} \))
- A \( 66.3 \times 10^{16} \text{ Hz} \)
- B \( 3.32 \times 10^{16} \text{ Hz} \)
- C \( 1.6 \times 10^{16} \text{ Hz} \)
- D \( 8.9 \times 10^{16} \text{ Hz} \)
Answer & Solution
Correct Answer
(C) \( 1.6 \times 10^{16} \text{ Hz} \)
Step-by-step Solution
Detailed explanation
\( f = \frac{E}{h} \) \( f = \frac{66.3 \text{ eV} \times (1.602 \times 10^{-19} \text{ J/eV})}{6.63 \times 10^{-34} \text{ Js}} \) \( f = 1.6 \times 10^{16} \text{ Hz} \)
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