CUET · PHYSICS · PYQ PAPER 2025
The frequency of a photon whose energy is 66.3 eV would be (Given \(h = 6.63 \times 10^{-34} \text{ Js}\))
- A \(66.3 \times 10^{16} \text{ Hz}\)
- B \(3.32 \times 10^{16} \text{ Hz}\)
- C \(1.6\times 10^{16} \text{ Hz}\)
- D \(8.9\times 10^{16} \text{ Hz}\)
Answer & Solution
Correct Answer
(C) \(1.6\times 10^{16} \text{ Hz}\)
Step-by-step Solution
Detailed explanation
\(f = \frac{E}{h} = \frac{66.3 \times 1.6 \times 10^{-19} \text{ J}}{6.63 \times 10^{-34} \text{ Js}}\) \(f = 1.6 \times 10^{16} \text{ Hz}\)
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