CUET · PHYSICS · PYQ PAPER 2023
The force between the plates of a parallel plate capacitor of capacitance C, distance between plates d and potential difference V is:
- A \( \frac{CV^2}{2d} \)
- B \( \frac{CV^2}{d} \)
- C \( \frac{C^2V^2}{4\pi\epsilon_0 d} \)
- D \( \frac{1}{2}\epsilon_0 \frac{V^2}{d^2} \)
Answer & Solution
Correct Answer
(A) \( \frac{CV^2}{2d} \)
Step-by-step Solution
Detailed explanation
\( F = Q \left( \frac{V}{2d} \right) \) \( F = (CV) \left( \frac{V}{2d} \right) = \frac{CV^2}{2d} \)
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