CUET · PHYSICS · PYQ PAPER 2023

The focal length of the objective of a microscope is \( f_o \) and that of the eye piece is \( f_e \). The aperture of objective is \( d_o \) and that of eye piece is \( d_e \). Which of the following relation is correct ?

A \( f_o > f_e, d_o > d_e \)
B \( f_o < f_e, d_o < d_e \)
C \( f_o > f_e, d_o < d_e \)
D \( f_o < f_e, d_o > d_e \)

Verified Solution

Answer & Solution

Correct Answer

(B) \( f_o < f_e, d_o < d_e \)

Step-by-step Solution

Detailed explanation

In a compound microscope, the objective lens has a very small focal length and aperture to achieve high initial magnification of tiny objects. The eyepiece has a relatively larger focal length and aperture to act as a magnifier and provide a wider field of view for the observer.…

Apply the relevant identity from the chapter and substitute the values established in the previous step, keeping the original constraint in view.

Use the simplified expression to isolate the unknown, then plug the result back into the question setup to confirm the working is internally consistent.

Cross-check against a boundary or limiting case. Both the dimensional balance and the qualitative behaviour at the extreme should agree with the candidate answer.

Combine the steps above to identify the correct option. The remaining choices each fail at least one of the consistency, dimensional, or boundary checks.

Same subject

Explore more questions on app

From CUET

Match List-l with List-ll

List-l Differential Equation	List-ll Integrating Factor
(A) \(y d x+\left(x-y^3\right) d y=0\)	(I) \(e^{-x}\)
(B) \(x \frac{d y}{d x}+y=x^2\)	(II) \(\frac{1}{x}\)
(C) \(\frac{d y}{d x}-y=e^x\)	(III) \(y\)
(D) \(x d y-y d x=x^3 d x\)	(IV) \(x\)

Choose the correct answer from the options given below :

CUET 2025 Hard

Explore more questions on app