CUET · PHYSICS · PYQ PAPER 2025
The first diffraction minima due to a single slit diffraction is at \(\theta=30^{\circ}\) for a light of wavelength \(5000 \AA\). The width of the slit is
- A \(1.5 \times 10^{-5} cm\)
- B \(1 \times 10^{-4} cm\)
- C \(2.5 \times 10^{-5} cm\)
- D \(1.25 \times 10^{-5} cm\)
Answer & Solution
Correct Answer
(B) \(1 \times 10^{-4} cm\)
Step-by-step Solution
Detailed explanation
\(a \sin\theta = n\lambda\) \(a = \frac{1 \times 5000 \times 10^{-10} m}{\sin 30^{\circ}}\) \(a = \frac{5 \times 10^{-7} m}{0.5} = 1 \times 10^{-6} m\) \(a = 1 \times 10^{-6} \times 10^2 cm = 1 \times 10^{-4} cm\)
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