CUET · PHYSICS · PYQ PAPER 2025
The external diameter of a 5 m long hollow copper tube is 10 cm and the wall thickness is 5 mm. If the specific resistance of copper is \( 1.7 \times 10^{-8} \text{ }\Omega\text{m} \), the resistance of the tube will be:
- A \( 7.45 \times 10^{-4} \text{ }\Omega \)
- B \( 14.9 \times 10^{-4} \text{ }\Omega \)
- C \( 5.7 \times 10^{-5} \text{ }\Omega \)
- D \( 5.7 \times 10^5 \text{ }\Omega \)
Answer & Solution
Correct Answer
(C) \( 5.7 \times 10^{-5} \text{ }\Omega \)
Step-by-step Solution
Detailed explanation
\( R_{ext} = \frac{10 \text{ cm}}{2} = 5 \text{ cm} = 0.05 \text{ m} \) \( R_{int} = 0.05 \text{ m} - 5 \text{ mm} = 0.05 \text{ m} - 0.005 \text{ m} = 0.045 \text{ m} \)…
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