CUET · PHYSICS · PYQ PAPER 2025
The energy of a photon is equal to the kinetic energy of a proton. The energy of the photon is E. Let \(\lambda_1\) be the de-Broglie wavelength of the proton and \(\lambda_2\) be the wavelength of the photon. The ratio \(\lambda_1/\lambda_2\) is proportional to the following
- A \(E^0\)
- B \(E^{1/2}\)
- C \(E^{-2}\)
- D \(E^{-1}\)
Answer & Solution
Correct Answer
(B) \(E^{1/2}\)
Step-by-step Solution
Detailed explanation
Photon wavelength: \(\lambda_2 = \frac{hc}{E}\) Proton de-Broglie wavelength: \(\lambda_1 = \frac{h}{p}\) Proton kinetic energy: \(E = \frac{p^2}{2m} \implies p = \sqrt{2mE}\) So, \(\lambda_1 = \frac{h}{\sqrt{2mE}}\) Ratio:…
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