CUET · PHYSICS · PYQ PAPER 2025
The electric potential at any point in space is given by \( V = 4x^2 \text{ volt} \). The electric field at the point (1 m, 0, 2 m) in SI unit is
- A 16, along the negative X- axis
- B 17.8, along the positive X- axis
- C 8, along the negative X- axis
- D 8, along the positive X- axis
Answer & Solution
Correct Answer
(C) 8, along the negative X- axis
Step-by-step Solution
Detailed explanation
\( \vec{E} = - \nabla V \) \( \vec{E} = - \left( \frac{\partial}{\partial x} (4x^2) \hat{i} + \frac{\partial}{\partial y} (4x^2) \hat{j} + \frac{\partial}{\partial z} (4x^2) \hat{k} \right) \) \( \vec{E} = - (8x \hat{i} + 0 \hat{j} + 0 \hat{k}) = -8x \hat{i} \) At (1 m, 0, 2 m):…
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