CUET · PHYSICS · PYQ PAPER 2023
The electric field intensity produced by the radiations coming from a 200 W bulb at 6 m distance is E . What is the electric field intensity produced by the radiations coming from 100 W bulb at the same distance?
- A \(\frac{E}{\sqrt{2}}\)
- B \(0.5 E\)
- C \(E \sqrt{2}\)
- D \(2 E\)
Answer & Solution
Correct Answer
(A) \(\frac{E}{\sqrt{2}}\)
Step-by-step Solution
Detailed explanation
\(E \propto \sqrt{P}\) \(\frac{E_{new}}{E} = \sqrt{\frac{P_{new}}{P_{old}}}\) \(E_{new} = E \sqrt{\frac{100\, \text{W}}{200\, \text{W}}} = E \sqrt{\frac{1}{2}}\) \(E_{new} = \frac{E}{\sqrt{2}}\)
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