CUET · PHYSICS · PYQ PAPER 2025
The electric field in a region is given by \( E = \frac{E_0 x}{b} \). Find the charge contained in the cubical volume bounded by the \( x = 0, x = a, y = 0, y = a \) and \( z = 0, z = a \). Take \( E_0 = 6 \times 10^3 \text{ N/C}, a = 1 \text{ cm} \) and \( b = 2 \text{ cm} \)
- A \( 2.2 \times 10^{-12} \text{ C} \)
- B \( 3.5 \times 10^{-12} \text{ C} \)
- C \( 7.4 \times 10^{-13} \text{ C} \)
- D \( 2.65 \times 10^{-12} \text{ C} \)
Answer & Solution
Correct Answer
(D) \( 2.65 \times 10^{-12} \text{ C} \)
Step-by-step Solution
Detailed explanation
\( \Phi = \oint \vec{E} \cdot d\vec{A} \) \( \vec{E} = \frac{E_0 x}{b} \hat{i} \) Flux is non-zero only through the face at \( x=a \). \( \Phi = E(a) \cdot A = \frac{E_0 a}{b} \cdot a^2 = \frac{E_0 a^3}{b} \) \( q_{enc} = \epsilon_0 \Phi = \epsilon_0 \frac{E_0 a^3}{b} \)…
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