CUET · PHYSICS · PYQ PAPER 2023
The electric field amplitude of an electromagnetic wave is \(100 N C ^{-1}\) and its frequency is 50 MHz . What is the magnitude of wave vector \(k\), (given speed of electromagnetic wave is \(3 \times 10^8 m s ^{-1}\) )
- A \(\frac{\pi}{6}\)
- B \(\frac{\pi}{3}\)
- C \(\frac{6}{\pi}\)
- D \(\frac{3}{\pi}\)
Answer & Solution
Correct Answer
(B) \(\frac{\pi}{3}\)
Step-by-step Solution
Detailed explanation
First, find the wavelength ( \(\lambda\) ) using the speed of light and frequency: \(\lambda=c / f=\) ( 3 \(\left.\times 10^8\right)\left(50 \times 10^6\right)=6 m\). Then, calculate the wave vector magnitude using the formula \(k=2 \pi / \lambda=2 \pi / 6\), which simplifies to…
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