CUET · PHYSICS · PYQ PAPER 2023
The distance between two point charges \(q_1 = 5\) mC and \(q_2 = -10\) mC in vacuum so that electrostatic force of attraction between them is 50 kN is :
- A 9 m
- B 3 m
- C 44 m
- D 10 m
Answer & Solution
Correct Answer
(B) 3 m
Step-by-step Solution
Detailed explanation
\(r = \sqrt{k \frac{|q_1 q_2|}{F}}\) \(r = \sqrt{\frac{(9 \times 10^9 \text{ N m}^2/\text{C}^2) \times |(5 \times 10^{-3} \text{ C})(-10 \times 10^{-3} \text{ C})|}{50 \times 10^3 \text{ N}}}\) \(r = 3 \text{ m}\)
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