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CUET · PHYSICS · PYQ PAPER 2023

The de Broglie wavelength of an electron having kinetic energy 56 eV is :

  1. A 0.022 nm
  2. B 16.4 \(\text{\AA}\)
  3. C 0.164 nm
  4. D 0.0164 nm
Verified Solution

Answer & Solution

Correct Answer

(C) 0.164 nm

Step-by-step Solution

Detailed explanation

\(\lambda = \frac{1.226}{\sqrt{E_k}}\text{ nm}\) \(\lambda = \frac{1.226}{\sqrt{56}}\text{ nm}\) \(\lambda \approx 0.164\text{ nm}\)