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CUET · PHYSICS · PYQ PAPER 2023

The de Broglie wavelength of an electron, a proton, and an alpha particle are represented by \(\lambda_e, \lambda_p, \lambda_\alpha\) respectively. If kinetic energy of electron, proton and alpha particle is same, then which of the following is correct.

  1. A \(\lambda_p > \lambda_e > \lambda_\alpha\)
  2. B \(\lambda_\alpha < \lambda_p < \lambda_e\)
  3. C \(\lambda_\alpha < \lambda_e < \lambda_p\)
  4. D \(\lambda_p < \lambda_\alpha < \lambda_e\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(\lambda_\alpha < \lambda_p < \lambda_e\)

Step-by-step Solution

Detailed explanation

\( \lambda = \frac{h}{\sqrt{2mK}} \) Since \( h \) and \( K \) are constant, \( \lambda \propto \frac{1}{\sqrt{m}} \). \( m_e \( \lambda_\alpha < \lambda_p < \lambda_e \)