CUET · PHYSICS · PYQ PAPER 2023
The de Broglie wavelength of an electron, a proton, and an alpha particle are represented by \(\lambda_e, \lambda_p, \lambda_\alpha\) respectively. If kinetic energy of electron, proton and alpha particle is same, then which of the following is correct.
- A \(\lambda_p > \lambda_e > \lambda_\alpha\)
- B \(\lambda_\alpha < \lambda_p < \lambda_e\)
- C \(\lambda_\alpha < \lambda_e < \lambda_p\)
- D \(\lambda_p < \lambda_\alpha < \lambda_e\)
Answer & Solution
Correct Answer
(B) \(\lambda_\alpha < \lambda_p < \lambda_e\)
Step-by-step Solution
Detailed explanation
\( \lambda = \frac{h}{\sqrt{2mK}} \) Since \( h \) and \( K \) are constant, \( \lambda \propto \frac{1}{\sqrt{m}} \). \( m_e \( \lambda_\alpha < \lambda_p < \lambda_e \)
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