CUET · PHYSICS · PYQ PAPER 2023
The de-Broglie wavelength associated with an electron accelerated through a potential difference V is \( \lambda \). The new de Broglie wavelength of electron when potential difference is increased to 9V will be:
- A \( 9\lambda \)
- B \( \lambda/3 \)
- C \( 3\lambda \)
- D \( \lambda/9 \)
Answer & Solution
Correct Answer
(B) \( \lambda/3 \)
Step-by-step Solution
Detailed explanation
\( \lambda \propto \frac{1}{\sqrt{V}} \) \( \lambda' = \lambda \sqrt{\frac{V}{9V}} \) \( \lambda' = \lambda \frac{1}{3} = \frac{\lambda}{3} \)
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