CUET · PHYSICS · PYQ PAPER 2023
The de Broglie wavelength associated with an electron accelerated through a potential difference of 100 V will be :
- A 0.0123 nm
- B 0.123 nm
- C 1.23 nm
- D 12.3 nm
Answer & Solution
Correct Answer
(B) 0.123 nm
Step-by-step Solution
Detailed explanation
\( \lambda = \frac{1.226}{\sqrt{V}} \) nm \( \lambda = \frac{1.226}{\sqrt{100}} \) nm \( \lambda = \frac{1.226}{10} \) nm \( \lambda = 0.1226 \) nm \( \lambda \approx 0.123 \) nm
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