CUET · PHYSICS · PYQ PAPER 2025
The current through a resistor in a circuit is 0.6 A. On putting a resistance of \(2 \Omega\) in parallel with the resistor, the current drops to 0.9 A. The resistance of the resistor is
- A \(1.0 \Omega\)
- B \(2.0 \Omega\)
- C \(4.0 \Omega\)
- D \(8.0 \Omega\)
Answer & Solution
Correct Answer
(A) \(1.0 \Omega\)
Step-by-step Solution
Detailed explanation
\(V = I_1 R\) \(V = 0.6 R\) \(V = I_2 \left( \frac{R \cdot 2}{R + 2} \right)\) \(V = 0.9 \left( \frac{2R}{R + 2} \right)\) \(0.6 R = 0.9 \left( \frac{2R}{R + 2} \right)\) \(0.6 = \frac{1.8}{R + 2}\) \(0.6(R + 2) = 1.8\) \(R + 2 = 3\) \(R = 1 \, \Omega\)
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