CUET · PHYSICS · PYQ PAPER 2025
The current in a device varies with time 't' as I = 6 t, where I is in mA and t is in s. The amount of charge that passes through the device during t = 0 s to t = 3 s is
- A 10 mC
- B 18 mC
- C 27 mC
- D 54 mC
Answer & Solution
Correct Answer
(C) 27 mC
Step-by-step Solution
Detailed explanation
\(Q = \int I dt\) \(Q = \int_{0}^{3} 6t dt = \left[ 3t^2 \right]_{0}^{3}\) \(Q = 3(3)^2 - 3(0)^2 = 27\) mC
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